Solve 3^5+27^2/9*3^5

$$\frac { 3 ^ { 5 } + 27 ^ { 2 } } { 9 \cdot 3 ^ { 5 } }$$

Evaluate

$$\frac{4}{9}\approx 0.444444444$$

Solution Steps

Calculate 3 to the power of 5 and get 243.

$$\frac{243+27^{2}}{9\times 3^{5}}$$

Calculate 27 to the power of 2 and get 729.

$$\frac{243+729}{9\times 3^{5}}$$

Add 243 and 729 to get 972.

$$\frac{972}{9\times 3^{5}}$$

Calculate 3 to the power of 5 and get 243.

$$\frac{972}{9\times 243}$$

Multiply 9 and 243 to get 2187.

$$\frac{972}{2187}$$

Reduce the fraction \frac{972}{2187} to lowest terms by extracting and canceling out 243.

$$\frac{4}{9}$$

Factor

$$\frac{2 ^ {2}}{3 ^ {2}} = 0.4444444444444444$$