Solve 3^3x+1/3^2/frac{1{3^5}}

$$\frac { 3 ^ { 3 x } + \frac { 1 } { 3 ^ { 2 } } } { \frac { 1 } { 3 ^ { 5 } } }$$

Factor

$$3^{3x+5}+27$$

Solution Steps

Calculate 3 to the power of 2 and get 9.

$$factor(\frac{3^{3x}+\frac{1}{9}}{\frac{1}{3^{5}}})$$

Calculate 3 to the power of 5 and get 243.

$$factor(\frac{3^{3x}+\frac{1}{9}}{\frac{1}{243}})$$

Divide 3^{3x}+\frac{1}{9} by \frac{1}{243} by multiplying 3^{3x}+\frac{1}{9} by the reciprocal of \frac{1}{243}.

$$factor(\left(3^{3x}+\frac{1}{9}\right)\times 243)$$

Use the distributive property to multiply 3^{3x}+\frac{1}{9} by 243.

$$factor(243\times 3^{3x}+27)$$

Factor out 27.

$$27\left(9\times 3^{3x}+1\right)$$

Evaluate

$$243\times 3^{3x}+27$$