Evaluate
4-3i
Real Part
4
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\frac{\left(3+4i\right)i}{1i^{2}}
Multiply both numerator and denominator by imaginary unit i.
\frac{\left(3+4i\right)i}{-1}
By definition, i^{2} is -1. Calculate the denominator.
\frac{3i+4i^{2}}{-1}
Multiply 3+4i times i.
\frac{3i+4\left(-1\right)}{-1}
By definition, i^{2} is -1.
\frac{-4+3i}{-1}
Do the multiplications in 3i+4\left(-1\right). Reorder the terms.
4-3i
Divide -4+3i by -1 to get 4-3i.
Re(\frac{\left(3+4i\right)i}{1i^{2}})
Multiply both numerator and denominator of \frac{3+4i}{i} by imaginary unit i.
Re(\frac{\left(3+4i\right)i}{-1})
By definition, i^{2} is -1. Calculate the denominator.
Re(\frac{3i+4i^{2}}{-1})
Multiply 3+4i times i.
Re(\frac{3i+4\left(-1\right)}{-1})
By definition, i^{2} is -1.
Re(\frac{-4+3i}{-1})
Do the multiplications in 3i+4\left(-1\right). Reorder the terms.
Re(4-3i)
Divide -4+3i by -1 to get 4-3i.
4
The real part of 4-3i is 4.
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Simultaneous equation
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Differentiation
\frac { d } { d x } \frac { ( 3 x ^ { 2 } - 2 ) } { ( x - 5 ) }
Integration
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Limits
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