Solve 3+4+9+10+12+15+17+27+47+48/10

$$\frac { 3 + 4 + 9 + 10 + 12 + 15 + 17 + 27 + 47 + 48 } { 10 }$$

Evaluate

$$\frac{96}{5}=19.2$$

Solution Steps

Add 3 and 4 to get 7.

$$\frac{7+9+10+12+15+17+27+47+48}{10}$$

Add 7 and 9 to get 16.

$$\frac{16+10+12+15+17+27+47+48}{10}$$

Add 16 and 10 to get 26.

$$\frac{26+12+15+17+27+47+48}{10}$$

Add 26 and 12 to get 38.

$$\frac{38+15+17+27+47+48}{10}$$

Add 38 and 15 to get 53.

$$\frac{53+17+27+47+48}{10}$$

Add 53 and 17 to get 70.

$$\frac{70+27+47+48}{10}$$

Add 70 and 27 to get 97.

$$\frac{97+47+48}{10}$$

Add 97 and 47 to get 144.

$$\frac{144+48}{10}$$

Add 144 and 48 to get 192.

$$\frac{192}{10}$$

Reduce the fraction \frac{192}{10} to lowest terms by extracting and canceling out 2.

$$\frac{96}{5}$$

Factor

$$\frac{2 ^ {5} \cdot 3}{5} = 19\frac{1}{5} = 19.2$$