Solve 3+3a/30-20bdiv1+a/5*3-2b/15

$$\frac { 3 + 3 a } { 30 - 20 b } \div \frac { 1 + a } { 5 } \times \frac { 3 - 2 b } { 15 }$$

Evaluate

$$\frac{1}{10}=0.1$$

Short Solution Steps

Divide \frac{3+3a}{30-20b} by \frac{1+a}{5} by multiplying \frac{3+3a}{30-20b} by the reciprocal of \frac{1+a}{5}.

$$\frac{\left(3+3a\right)\times 5}{\left(30-20b\right)\left(1+a\right)}\times \frac{3-2b}{15}$$

Factor the expressions that are not already factored in \frac{\left(3+3a\right)\times 5}{\left(30-20b\right)\left(1+a\right)}.

$$\frac{3\times 5\left(a+1\right)}{10\left(a+1\right)\left(-2b+3\right)}\times \frac{3-2b}{15}$$

Cancel out 5\left(a+1\right) in both numerator and denominator.

$$\frac{3}{2\left(-2b+3\right)}\times \frac{3-2b}{15}$$

Multiply \frac{3}{2\left(-2b+3\right)} times \frac{3-2b}{15} by multiplying numerator times numerator and denominator times denominator.

$$\frac{3\left(3-2b\right)}{2\left(-2b+3\right)\times 15}$$

Cancel out 3\left(-2b+3\right) in both numerator and denominator.

$$\frac{1}{2\times 5}$$

Multiply 2 and 5 to get 10.

$$\frac{1}{10}$$

Factor

$$\frac{1}{2 \cdot 5} = 0.1$$