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\frac{\left(3+\sqrt{14}\right)\left(8-\sqrt{14}\right)}{\left(8+\sqrt{14}\right)\left(8-\sqrt{14}\right)}
Rationalize the denominator of \frac{3+\sqrt{14}}{8+\sqrt{14}} by multiplying numerator and denominator by 8-\sqrt{14}.
\frac{\left(3+\sqrt{14}\right)\left(8-\sqrt{14}\right)}{8^{2}-\left(\sqrt{14}\right)^{2}}
Consider \left(8+\sqrt{14}\right)\left(8-\sqrt{14}\right). Multiplication can be transformed into difference of squares using the rule: \left(a-b\right)\left(a+b\right)=a^{2}-b^{2}.
\frac{\left(3+\sqrt{14}\right)\left(8-\sqrt{14}\right)}{64-14}
Square 8. Square \sqrt{14}.
\frac{\left(3+\sqrt{14}\right)\left(8-\sqrt{14}\right)}{50}
Subtract 14 from 64 to get 50.
\frac{24-3\sqrt{14}+8\sqrt{14}-\left(\sqrt{14}\right)^{2}}{50}
Apply the distributive property by multiplying each term of 3+\sqrt{14} by each term of 8-\sqrt{14}.
\frac{24+5\sqrt{14}-\left(\sqrt{14}\right)^{2}}{50}
Combine -3\sqrt{14} and 8\sqrt{14} to get 5\sqrt{14}.
\frac{24+5\sqrt{14}-14}{50}
The square of \sqrt{14} is 14.
\frac{10+5\sqrt{14}}{50}
Subtract 14 from 24 to get 10.