Solve 3+3/8*6+83/6/1,2=

$$\frac { 3 + \frac { 3 } { 8 } \times 6 + 8 \frac { 3 } { 6 } } { 1,2 } =$$

Evaluate

$$\frac{275}{24}\approx 11,458333333$$

Solution Steps

Express \frac{3}{8}\times 6 as a single fraction.

$$\frac{3+\frac{3\times 6}{8}+\frac{8\times 6+3}{6}}{1,2}$$

Multiply 3 and 6 to get 18.

$$\frac{3+\frac{18}{8}+\frac{8\times 6+3}{6}}{1,2}$$

Reduce the fraction \frac{18}{8} to lowest terms by extracting and canceling out 2.

$$\frac{3+\frac{9}{4}+\frac{8\times 6+3}{6}}{1,2}$$

Convert 3 to fraction \frac{12}{4}.

$$\frac{\frac{12}{4}+\frac{9}{4}+\frac{8\times 6+3}{6}}{1,2}$$

Since \frac{12}{4} and \frac{9}{4} have the same denominator, add them by adding their numerators.

$$\frac{\frac{12+9}{4}+\frac{8\times 6+3}{6}}{1,2}$$

Add 12 and 9 to get 21.

$$\frac{\frac{21}{4}+\frac{8\times 6+3}{6}}{1,2}$$

Multiply 8 and 6 to get 48.

$$\frac{\frac{21}{4}+\frac{48+3}{6}}{1,2}$$

Add 48 and 3 to get 51.

$$\frac{\frac{21}{4}+\frac{51}{6}}{1,2}$$

Reduce the fraction \frac{51}{6} to lowest terms by extracting and canceling out 3.

$$\frac{\frac{21}{4}+\frac{17}{2}}{1,2}$$

Least common multiple of 4 and 2 is 4. Convert \frac{21}{4} and \frac{17}{2} to fractions with denominator 4.

$$\frac{\frac{21}{4}+\frac{34}{4}}{1,2}$$

Since \frac{21}{4} and \frac{34}{4} have the same denominator, add them by adding their numerators.

$$\frac{\frac{21+34}{4}}{1,2}$$

Add 21 and 34 to get 55.

$$\frac{\frac{55}{4}}{1,2}$$

Express \frac{\frac{55}{4}}{1,2} as a single fraction.

$$\frac{55}{4\times 1,2}$$

Multiply 4 and 1,2 to get 4,8.

$$\frac{55}{4,8}$$

Expand \frac{55}{4,8} by multiplying both numerator and the denominator by 10.

$$\frac{550}{48}$$

Reduce the fraction \frac{550}{48} to lowest terms by extracting and canceling out 2.

$$\frac{275}{24}$$

Factor

$$\frac{11 \cdot 5 ^ {2}}{3 \cdot 2 ^ {3}} = 11\frac{11}{24} = 11.458333333333334$$