Solve 3!+2!/(0!+1!)^2=2

$$\frac { 3 ! + 2 ! } { ( 0 ! + 1 ! ) ^ { 2 } } = 2$$

Verify

Solution Steps

The factorial of 3 is 6.

$$\frac{6+2!}{\left(0!+1!\right)^{2}}=2$$

The factorial of 2 is 2.

$$\frac{6+2}{\left(0!+1!\right)^{2}}=2$$

Add 6 and 2 to get 8.

$$\frac{8}{\left(0!+1!\right)^{2}}=2$$

The factorial of 0 is 1.

$$\frac{8}{\left(1+1!\right)^{2}}=2$$

The factorial of 1 is 1.

$$\frac{8}{\left(1+1\right)^{2}}=2$$

Add 1 and 1 to get 2.

$$\frac{8}{2^{2}}=2$$

Calculate 2 to the power of 2 and get 4.

$$\frac{8}{4}=2$$

Divide 8 by 4 to get 2.

$$2=2$$

Compare 2 and 2.

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