Solve 29/6-(-45/24)

$$\frac { 29 } { 6 } - ( - \frac { 45 } { 24 } )$$

Evaluate

$$\frac{161}{24}\approx 6.708333333$$

Solution Steps

Reduce the fraction \frac{45}{24} to lowest terms by extracting and canceling out 3.

$$\frac{29}{6}-\left(-\frac{15}{8}\right)$$

The opposite of -\frac{15}{8} is \frac{15}{8}.

$$\frac{29}{6}+\frac{15}{8}$$

Least common multiple of 6 and 8 is 24. Convert \frac{29}{6} and \frac{15}{8} to fractions with denominator 24.

$$\frac{116}{24}+\frac{45}{24}$$

Since \frac{116}{24} and \frac{45}{24} have the same denominator, add them by adding their numerators.

$$\frac{116+45}{24}$$

Add 116 and 45 to get 161.

$$\frac{161}{24}$$

Factor

$$\frac{7 \cdot 23}{2 ^ {3} \cdot 3} = 6\frac{17}{24} = 6.708333333333333$$