Solve 28div2^3/4^3*2*1=

$$\frac { 28 \div 2 ^ { 3 } } { 4 ^ { 3 } \times 2 } \cdot 1 =$$

Evaluate

$$\frac{7}{256}=0.02734375$$

Solution Steps

Calculate 2 to the power of 3 and get 8.

$$\frac{\frac{28}{8}}{4^{3}\times 2}\times 1$$

Reduce the fraction \frac{28}{8} to lowest terms by extracting and canceling out 4.

$$\frac{\frac{7}{2}}{4^{3}\times 2}\times 1$$

Calculate 4 to the power of 3 and get 64.

$$\frac{\frac{7}{2}}{64\times 2}\times 1$$

Multiply 64 and 2 to get 128.

$$\frac{\frac{7}{2}}{128}\times 1$$

Express \frac{\frac{7}{2}}{128} as a single fraction.

$$\frac{7}{2\times 128}\times 1$$

Multiply 2 and 128 to get 256.

$$\frac{7}{256}\times 1$$

Multiply \frac{7}{256} and 1 to get \frac{7}{256}.

$$\frac{7}{256}$$

Factor

$$\frac{7}{2 ^ {8}} = 0.02734375$$