Solve 27xy/8x*4x^2/3xy^3

$$\frac { 27 x y } { 8 x } \cdot \frac { 4 x ^ { 2 } } { 3 x y ^ { 3 } }$$

Evaluate

$$\frac{9x}{2y^{2}}$$

Solution Steps

Cancel out x in both numerator and denominator.

$$\frac{27y}{8}\times \frac{4x^{2}}{3xy^{3}}$$

Cancel out x in both numerator and denominator.

$$\frac{27y}{8}\times \frac{4x}{3y^{3}}$$

Multiply \frac{27y}{8} times \frac{4x}{3y^{3}} by multiplying numerator times numerator and denominator times denominator.

$$\frac{27y\times 4x}{8\times 3y^{3}}$$

Cancel out 3\times 4y in both numerator and denominator.

$$\frac{9x}{2y^{2}}$$

Differentiate w.r.t. x

$$\frac{9}{2y^{2}}$$