Solve 27x^3+27x^2+9x+1/9+c

$$\frac { 27 x ^ { 3 } + 27 x ^ { 2 } + 9 x + 1 } { 9 } + c$$

Evaluate

$$3x^{3}+3x^{2}+x+c+\frac{1}{9}$$

Short Solution Steps

To add or subtract expressions, expand them to make their denominators the same. Multiply c times \frac{9}{9}.

$$\frac{27x^{3}+27x^{2}+9x+1}{9}+\frac{9c}{9}$$

Since \frac{27x^{3}+27x^{2}+9x+1}{9} and \frac{9c}{9} have the same denominator, add them by adding their numerators.

$$\frac{27x^{3}+27x^{2}+9x+1+9c}{9}$$

Expand

$$3x^{3}+3x^{2}+x+c+\frac{1}{9}$$

Short Solution Steps

To add or subtract expressions, expand them to make their denominators the same. Multiply c times \frac{9}{9}.

$$\frac{27x^{3}+27x^{2}+9x+1}{9}+\frac{9c}{9}$$

Since \frac{27x^{3}+27x^{2}+9x+1}{9} and \frac{9c}{9} have the same denominator, add them by adding their numerators.

$$\frac{27x^{3}+27x^{2}+9x+1+9c}{9}$$