Solve 27-1/51*(-1/3)/1+frac{1{3}}

$$\frac { 27 - \frac { 1 } { 51 } \times ( - \frac { 1 } { 3 } ) } { 1 + \frac { 1 } { 3 } }$$

Evaluate

$$\frac{1033}{51}\approx 20.254901961$$

Solution Steps

Multiply \frac{1}{51} times -\frac{1}{3} by multiplying numerator times numerator and denominator times denominator.

$$\frac{27-\frac{1\left(-1\right)}{51\times 3}}{1+\frac{1}{3}}$$

Do the multiplications in the fraction \frac{1\left(-1\right)}{51\times 3}.

$$\frac{27-\frac{-1}{153}}{1+\frac{1}{3}}$$

Fraction \frac{-1}{153} can be rewritten as -\frac{1}{153} by extracting the negative sign.

$$\frac{27-\left(-\frac{1}{153}\right)}{1+\frac{1}{3}}$$

The opposite of -\frac{1}{153} is \frac{1}{153}.

$$\frac{27+\frac{1}{153}}{1+\frac{1}{3}}$$

Convert 27 to fraction \frac{4131}{153}.

$$\frac{\frac{4131}{153}+\frac{1}{153}}{1+\frac{1}{3}}$$

Since \frac{4131}{153} and \frac{1}{153} have the same denominator, add them by adding their numerators.

$$\frac{\frac{4131+1}{153}}{1+\frac{1}{3}}$$

Add 4131 and 1 to get 4132.

$$\frac{\frac{4132}{153}}{1+\frac{1}{3}}$$

Convert 1 to fraction \frac{3}{3}.

$$\frac{\frac{4132}{153}}{\frac{3}{3}+\frac{1}{3}}$$

Since \frac{3}{3} and \frac{1}{3} have the same denominator, add them by adding their numerators.

$$\frac{\frac{4132}{153}}{\frac{3+1}{3}}$$

Add 3 and 1 to get 4.

$$\frac{\frac{4132}{153}}{\frac{4}{3}}$$

Divide \frac{4132}{153} by \frac{4}{3} by multiplying \frac{4132}{153} by the reciprocal of \frac{4}{3}.

$$\frac{4132}{153}\times \frac{3}{4}$$

Multiply \frac{4132}{153} times \frac{3}{4} by multiplying numerator times numerator and denominator times denominator.

$$\frac{4132\times 3}{153\times 4}$$

Do the multiplications in the fraction \frac{4132\times 3}{153\times 4}.

$$\frac{12396}{612}$$

Reduce the fraction \frac{12396}{612} to lowest terms by extracting and canceling out 12.

$$\frac{1033}{51}$$

Factor

$$\frac{1033}{3 \cdot 17} = 20\frac{13}{51} = 20.254901960784313$$