Factor
\frac{\left(3x^{4}+10y^{3}\right)\left(9x^{8}+100y^{6}-30y^{3}x^{4}\right)}{8}
Evaluate
\frac{27x^{12}}{8}+125y^{9}
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\frac{27x^{12}+1000y^{9}}{8}
Factor out \frac{1}{8}.
\left(3x^{4}+10y^{3}\right)\left(9x^{8}+100y^{6}-30y^{3}x^{4}\right)
Consider 27x^{12}+1000y^{9}. Rewrite 27x^{12}+1000y^{9} as \left(3x^{4}\right)^{3}+\left(10y^{3}\right)^{3}. The sum of cubes can be factored using the rule: a^{3}+b^{3}=\left(a+b\right)\left(a^{2}-ab+b^{2}\right).
\frac{\left(3x^{4}+10y^{3}\right)\left(9x^{8}+100y^{6}-30y^{3}x^{4}\right)}{8}
Rewrite the complete factored expression.
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