Solve 25x+3/7+x-1/2leq-4

$$\frac { 25 x + 3 } { 7 } + \frac { x - 1 } { 2 } \leq - 4$$

Solve for x

$$x\leq -\frac{55}{57}$$

Solution Steps

Multiply both sides of the equation by 14, the least common multiple of 7,2. Since 14 is positive, the inequality direction remains the same.

$$2\left(25x+3\right)+7\left(x-1\right)\leq -56$$

Use the distributive property to multiply 2 by 25x+3.

$$50x+6+7\left(x-1\right)\leq -56$$

Use the distributive property to multiply 7 by x-1.

$$50x+6+7x-7\leq -56$$

Combine 50x and 7x to get 57x.

$$57x+6-7\leq -56$$

Subtract 7 from 6 to get -1.

$$57x-1\leq -56$$

Add 1 to both sides.

$$57x\leq -56+1$$

Add -56 and 1 to get -55.

$$57x\leq -55$$

Divide both sides by 57. Since 57 is positive, the inequality direction remains the same.

$$x\leq -\frac{55}{57}$$