Solve 25/3+45/2-7/6-1/12

$$\frac { 25 } { 3 } + 4 \frac { 5 } { 2 } - \frac { 7 } { 6 } - \frac { 1 } { 12 }$$

Evaluate

$$\frac{163}{12}\approx 13.583333333$$

Solution Steps

Multiply 4 and 2 to get 8.

$$\frac{25}{3}+\frac{8+5}{2}-\frac{7}{6}-\frac{1}{12}$$

Add 8 and 5 to get 13.

$$\frac{25}{3}+\frac{13}{2}-\frac{7}{6}-\frac{1}{12}$$

Least common multiple of 3 and 2 is 6. Convert \frac{25}{3} and \frac{13}{2} to fractions with denominator 6.

$$\frac{50}{6}+\frac{39}{6}-\frac{7}{6}-\frac{1}{12}$$

Since \frac{50}{6} and \frac{39}{6} have the same denominator, add them by adding their numerators.

$$\frac{50+39}{6}-\frac{7}{6}-\frac{1}{12}$$

Add 50 and 39 to get 89.

$$\frac{89}{6}-\frac{7}{6}-\frac{1}{12}$$

Since \frac{89}{6} and \frac{7}{6} have the same denominator, subtract them by subtracting their numerators.

$$\frac{89-7}{6}-\frac{1}{12}$$

Subtract 7 from 89 to get 82.

$$\frac{82}{6}-\frac{1}{12}$$

Reduce the fraction \frac{82}{6} to lowest terms by extracting and canceling out 2.

$$\frac{41}{3}-\frac{1}{12}$$

Least common multiple of 3 and 12 is 12. Convert \frac{41}{3} and \frac{1}{12} to fractions with denominator 12.

$$\frac{164}{12}-\frac{1}{12}$$

Since \frac{164}{12} and \frac{1}{12} have the same denominator, subtract them by subtracting their numerators.

$$\frac{164-1}{12}$$

Subtract 1 from 164 to get 163.

$$\frac{163}{12}$$

Factor

$$\frac{163}{2 ^ {2} \cdot 3} = 13\frac{7}{12} = 13.583333333333334$$