Solve for x
x=840
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\frac{83}{84}x+10=x
Combine \frac{25}{252}x and \frac{8}{9}x to get \frac{83}{84}x.
\frac{83}{84}x+10-x=0
Subtract x from both sides.
-\frac{1}{84}x+10=0
Combine \frac{83}{84}x and -x to get -\frac{1}{84}x.
-\frac{1}{84}x=-10
Subtract 10 from both sides. Anything subtracted from zero gives its negation.
x=-10\left(-84\right)
Multiply both sides by -84, the reciprocal of -\frac{1}{84}.
x=840
Multiply -10 and -84 to get 840.
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