Solve 25*a^3*(-b^5)/3^2*a*b^6=

$$\frac { 25 \cdot a ^ { 3 } \cdot ( - b ^ { 5 } ) } { 3 ^ { 2 } \cdot a \cdot b ^ { 6 } } =$$

Evaluate

$$-\frac{25a^{2}}{9b}$$

Short Solution Steps

Cancel out a in both numerator and denominator.

$$\frac{25a^{2}\left(-b^{5}\right)}{3^{2}b^{6}}$$

Calculate 3 to the power of 2 and get 9.

$$\frac{25a^{2}\left(-b^{5}\right)}{9b^{6}}$$

Factor the expressions that are not already factored.

$$\frac{-25a^{2}b^{5}}{9b^{6}}$$

Cancel out b^{5} in both numerator and denominator.

$$\frac{-25a^{2}}{9b}$$

Differentiate w.r.t. b

$$\frac{25\times \left(\frac{a}{b}\right)^{2}}{9}$$