Solve frac{25^{circ}*5}{9^{0}*(-2)^2*(-5)^3}*(20div4)^2/(8+6)^3-3

$$\frac { 25 ^ { \circ } \cdot 5 } { 9 ^ { 0 } \cdot ( - 2 ) ^ { 2 } \cdot ( - 5 ) ^ { 3 } } \cdot \frac { ( 20 \div 4 ) ^ { 2 } } { ( 8 + 6 ) ^ { 3 - 3 } }$$

Evaluate

$$-\frac{25}{4}=-6.25$$

Solution Steps

Multiply 25 and 5 to get 125.

$$\frac{125}{9^{0}\left(-2\right)^{2}\left(-5\right)^{3}}\times \frac{\left(\frac{20}{4}\right)^{2}}{\left(8+6\right)^{3-3}}$$

Calculate 9 to the power of 0 and get 1.

$$\frac{125}{1\left(-2\right)^{2}\left(-5\right)^{3}}\times \frac{\left(\frac{20}{4}\right)^{2}}{\left(8+6\right)^{3-3}}$$

Calculate -2 to the power of 2 and get 4.

$$\frac{125}{1\times 4\left(-5\right)^{3}}\times \frac{\left(\frac{20}{4}\right)^{2}}{\left(8+6\right)^{3-3}}$$

Multiply 1 and 4 to get 4.

$$\frac{125}{4\left(-5\right)^{3}}\times \frac{\left(\frac{20}{4}\right)^{2}}{\left(8+6\right)^{3-3}}$$

Calculate -5 to the power of 3 and get -125.

$$\frac{125}{4\left(-125\right)}\times \frac{\left(\frac{20}{4}\right)^{2}}{\left(8+6\right)^{3-3}}$$

Multiply 4 and -125 to get -500.

$$\frac{125}{-500}\times \frac{\left(\frac{20}{4}\right)^{2}}{\left(8+6\right)^{3-3}}$$

Reduce the fraction \frac{125}{-500} to lowest terms by extracting and canceling out 125.

$$-\frac{1}{4}\times \frac{\left(\frac{20}{4}\right)^{2}}{\left(8+6\right)^{3-3}}$$

Divide 20 by 4 to get 5.

$$-\frac{1}{4}\times \frac{5^{2}}{\left(8+6\right)^{3-3}}$$

Calculate 5 to the power of 2 and get 25.

$$-\frac{1}{4}\times \frac{25}{\left(8+6\right)^{3-3}}$$

Add 8 and 6 to get 14.

$$-\frac{1}{4}\times \frac{25}{14^{3-3}}$$

Subtract 3 from 3 to get 0.

$$-\frac{1}{4}\times \frac{25}{14^{0}}$$

Calculate 14 to the power of 0 and get 1.

$$-\frac{1}{4}\times \frac{25}{1}$$

Anything divided by one gives itself.

$$-\frac{1}{4}\times 25$$

Multiply -\frac{1}{4} and 25 to get -\frac{25}{4}.

$$-\frac{25}{4}$$

Factor

$$-\frac{25}{4} = -6\frac{1}{4} = -6.25$$