Solve 24/16quad3/11-7/121quad7/9

$$\frac { 24 } { 16 } \quad \frac { 3 } { 11 } - \frac { 7 } { 121 } \quad \frac { 7 } { 9 }$$

Evaluate

$$\frac{793}{2178}\approx 0.3640955$$

Solution Steps

Reduce the fraction \frac{24}{16} to lowest terms by extracting and canceling out 8.

$$\frac{3}{2}\times \frac{3}{11}-\frac{7}{121}\times \frac{7}{9}$$

Multiply \frac{3}{2} times \frac{3}{11} by multiplying numerator times numerator and denominator times denominator.

$$\frac{3\times 3}{2\times 11}-\frac{7}{121}\times \frac{7}{9}$$

Do the multiplications in the fraction \frac{3\times 3}{2\times 11}.

$$\frac{9}{22}-\frac{7}{121}\times \frac{7}{9}$$

Multiply \frac{7}{121} times \frac{7}{9} by multiplying numerator times numerator and denominator times denominator.

$$\frac{9}{22}-\frac{7\times 7}{121\times 9}$$

Do the multiplications in the fraction \frac{7\times 7}{121\times 9}.

$$\frac{9}{22}-\frac{49}{1089}$$

Least common multiple of 22 and 1089 is 2178. Convert \frac{9}{22} and \frac{49}{1089} to fractions with denominator 2178.

$$\frac{891}{2178}-\frac{98}{2178}$$

Since \frac{891}{2178} and \frac{98}{2178} have the same denominator, subtract them by subtracting their numerators.

$$\frac{891-98}{2178}$$

Subtract 98 from 891 to get 793.

$$\frac{793}{2178}$$

Factor

$$\frac{13 \cdot 61}{2 \cdot 3 ^ {2} \cdot 11 ^ {2}} = 0.3640955004591368$$