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\frac{24+6\sqrt{3}}{6}
Factor 108=6^{2}\times 3. Rewrite the square root of the product \sqrt{6^{2}\times 3} as the product of square roots \sqrt{6^{2}}\sqrt{3}. Take the square root of 6^{2}.
4+\sqrt{3}
Divide each term of 24+6\sqrt{3} by 6 to get 4+\sqrt{3}.