Solve 210000/100000*26,5^2+30,5^2=

$$\frac { 210000 } { 100000 } \cdot 26,5 ^ { 2 } + 30,5 ^ { 2 } =$$

Evaluate

$$2115$$

Solution Steps

Reduce the fraction \frac{210000}{100000} to lowest terms by extracting and canceling out 10000.

$$\frac{21}{10}\times 26\times 5^{2}+30\times 5^{2}$$

Express \frac{21}{10}\times 26 as a single fraction.

$$\frac{21\times 26}{10}\times 5^{2}+30\times 5^{2}$$

Multiply 21 and 26 to get 546.

$$\frac{546}{10}\times 5^{2}+30\times 5^{2}$$

Reduce the fraction \frac{546}{10} to lowest terms by extracting and canceling out 2.

$$\frac{273}{5}\times 5^{2}+30\times 5^{2}$$

Calculate 5 to the power of 2 and get 25.

$$\frac{273}{5}\times 25+30\times 5^{2}$$

Express \frac{273}{5}\times 25 as a single fraction.

$$\frac{273\times 25}{5}+30\times 5^{2}$$

Multiply 273 and 25 to get 6825.

$$\frac{6825}{5}+30\times 5^{2}$$

Divide 6825 by 5 to get 1365.

$$1365+30\times 5^{2}$$

Calculate 5 to the power of 2 and get 25.

$$1365+30\times 25$$

Multiply 30 and 25 to get 750.

$$1365+750$$

Add 1365 and 750 to get 2115.

$$2115$$

Factor

$$3^{2}\times 5\times 47$$