Solve 21x^3y^4/7x^3y^4

$$\frac { 21 x ^ { 3 } y ^ { 4 } } { 7 x ^ { 3 } y ^ { 4 } }$$

Evaluate

$$3$$

Steps Using Quotient of Powers Property

Use the rules of exponents to simplify the expression.

$$\frac{21^{1}x^{3}y^{4}}{7^{1}x^{3}y^{4}}$$

To divide powers of the same base, subtract the denominator's exponent from the numerator's exponent.

$$\frac{21^{1}}{7^{1}}x^{3-3}y^{4-4}$$

Subtract 3 from 3.

$$\frac{21^{1}}{7^{1}}x^{0}y^{4-4}$$

For any number a except 0, a^{0}=1.

$$\frac{21^{1}}{7^{1}}y^{4-4}$$

Subtract 4 from 4.

$$\frac{21^{1}}{7^{1}}y^{0}$$

For any number a except 0, a^{0}=1.

$$\frac{21^{1}}{7^{1}}$$

Divide 21 by 7.

$$3$$

Factor

$$3$$