Solve 21a^5b^4/49a^2b^3

$$\frac { 21 a ^ { 5 } b ^ { 4 } } { 49 a ^ { 2 } b ^ { 3 } }$$

Evaluate

$$\frac{3ba^{3}}{7}$$

Steps Using Quotient of Powers Property

Use the rules of exponents to simplify the expression.

$$\frac{21^{1}a^{5}b^{4}}{49^{1}a^{2}b^{3}}$$

To divide powers of the same base, subtract the denominator's exponent from the numerator's exponent.

$$\frac{21^{1}}{49^{1}}a^{5-2}b^{4-3}$$

Subtract 2 from 5.

$$\frac{21^{1}}{49^{1}}a^{3}b^{4-3}$$

Subtract 3 from 4.

$$\frac{21^{1}}{49^{1}}a^{3}b^{1}$$

Reduce the fraction \frac{21}{49} to lowest terms by extracting and canceling out 7.

$$\frac{3}{7}a^{3}b$$

Differentiate w.r.t. b

$$\frac{3a^{3}}{7}$$