Solve 21/3-3/10*(2,2-0,3)-0,12

$$\frac { 21 } { 3 } - \frac { 3 } { 10 } \cdot ( 2,2 - 0,3 ) - 0,12$$

Evaluate

$$6,31$$

Solution Steps

Divide 21 by 3 to get 7.

$$7-\frac{3}{10}\left(2,2-0,3\right)-0,12$$

Subtract 0,3 from 2,2 to get 1,9.

$$7-\frac{3}{10}\times 1,9-0,12$$

Convert decimal number 1,9 to fraction \frac{19}{10}.

$$7-\frac{3}{10}\times \frac{19}{10}-0,12$$

Multiply \frac{3}{10} times \frac{19}{10} by multiplying numerator times numerator and denominator times denominator.

$$7-\frac{3\times 19}{10\times 10}-0,12$$

Do the multiplications in the fraction \frac{3\times 19}{10\times 10}.

$$7-\frac{57}{100}-0,12$$

Convert 7 to fraction \frac{700}{100}.

$$\frac{700}{100}-\frac{57}{100}-0,12$$

Since \frac{700}{100} and \frac{57}{100} have the same denominator, subtract them by subtracting their numerators.

$$\frac{700-57}{100}-0,12$$

Subtract 57 from 700 to get 643.

$$\frac{643}{100}-0,12$$

Convert decimal number 0,12 to fraction \frac{12}{100}. Reduce the fraction \frac{12}{100} to lowest terms by extracting and canceling out 4.

$$\frac{643}{100}-\frac{3}{25}$$

Least common multiple of 100 and 25 is 100. Convert \frac{643}{100} and \frac{3}{25} to fractions with denominator 100.

$$\frac{643}{100}-\frac{12}{100}$$

Since \frac{643}{100} and \frac{12}{100} have the same denominator, subtract them by subtracting their numerators.

$$\frac{643-12}{100}$$

Subtract 12 from 643 to get 631.

$$\frac{631}{100}$$

Factor

$$\frac{631}{2 ^ {2} \cdot 5 ^ {2}} = 6\frac{31}{100} = 6.31$$