Solve for x
x = \frac{40}{3} = 13\frac{1}{3} \approx 13.333333333
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42+4x+10\times 4+1+4x+4x=60\times 4+3
Multiply both sides of the equation by 4, the least common multiple of 2,4.
42+4x+40+1+4x+4x=60\times 4+3
Multiply 10 and 4 to get 40.
82+4x+1+4x+4x=60\times 4+3
Add 42 and 40 to get 82.
83+4x+4x+4x=60\times 4+3
Add 82 and 1 to get 83.
83+8x+4x=60\times 4+3
Combine 4x and 4x to get 8x.
83+12x=60\times 4+3
Combine 8x and 4x to get 12x.
83+12x=240+3
Multiply 60 and 4 to get 240.
83+12x=243
Add 240 and 3 to get 243.
12x=243-83
Subtract 83 from both sides.
12x=160
Subtract 83 from 243 to get 160.
x=\frac{160}{12}
Divide both sides by 12.
x=\frac{40}{3}
Reduce the fraction \frac{160}{12} to lowest terms by extracting and canceling out 4.
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