Solve 2000^3-2*2000^2-199/2000^3+2000^2-2001

$$\frac { 2000 ^ { 3 } - 2 \times 2000 ^ { 2 } - 199 } { 2000 ^ { 3 } + 2000 ^ { 2 } - 2001 }$$

Evaluate

$$\frac{7991999801}{8003997999}\approx 0.998500974$$

Solution Steps

Calculate 2000 to the power of 3 and get 8000000000.

$$\frac{8000000000-2\times 2000^{2}-199}{2000^{3}+2000^{2}-2001}$$

Calculate 2000 to the power of 2 and get 4000000.

$$\frac{8000000000-2\times 4000000-199}{2000^{3}+2000^{2}-2001}$$

Multiply 2 and 4000000 to get 8000000.

$$\frac{8000000000-8000000-199}{2000^{3}+2000^{2}-2001}$$

Subtract 8000000 from 8000000000 to get 7992000000.

$$\frac{7992000000-199}{2000^{3}+2000^{2}-2001}$$

Subtract 199 from 7992000000 to get 7991999801.

$$\frac{7991999801}{2000^{3}+2000^{2}-2001}$$

Calculate 2000 to the power of 3 and get 8000000000.

$$\frac{7991999801}{8000000000+2000^{2}-2001}$$

Calculate 2000 to the power of 2 and get 4000000.

$$\frac{7991999801}{8000000000+4000000-2001}$$

Add 8000000000 and 4000000 to get 8004000000.

$$\frac{7991999801}{8004000000-2001}$$

Subtract 2001 from 8004000000 to get 8003997999.

$$\frac{7991999801}{8003997999}$$

Factor

$$\frac{151 \cdot 52927151}{3 ^ {2} \cdot 23 ^ {2} \cdot 29 ^ {2} \cdot 1999} = 0.9985009743878623$$