Solve 2000^2+3800^2-2900^2/7(2000)(3800)

$$\frac { 2000 ^ { 2 } + 3800 ^ { 2 } - 2900 ^ { 2 } } { 7 ( 2000 ) ( 3800 ) }$$

Evaluate

$$\frac{1003}{5320}\approx 0.188533835$$

Solution Steps

Calculate 2000 to the power of 2 and get 4000000.

$$\frac{4000000+3800^{2}-2900^{2}}{7\times 2000\times 3800}$$

Calculate 3800 to the power of 2 and get 14440000.

$$\frac{4000000+14440000-2900^{2}}{7\times 2000\times 3800}$$

Add 4000000 and 14440000 to get 18440000.

$$\frac{18440000-2900^{2}}{7\times 2000\times 3800}$$

Calculate 2900 to the power of 2 and get 8410000.

$$\frac{18440000-8410000}{7\times 2000\times 3800}$$

Subtract 8410000 from 18440000 to get 10030000.

$$\frac{10030000}{7\times 2000\times 3800}$$

Multiply 7 and 2000 to get 14000.

$$\frac{10030000}{14000\times 3800}$$

Multiply 14000 and 3800 to get 53200000.

$$\frac{10030000}{53200000}$$

Reduce the fraction \frac{10030000}{53200000} to lowest terms by extracting and canceling out 10000.

$$\frac{1003}{5320}$$

Factor

$$\frac{17 \cdot 59}{2 ^ {3} \cdot 5 \cdot 7 \cdot 19} = 0.18853383458646616$$