Solve 20/3+20/8-1/2=1

$$\frac { 20 } { 3 } + \frac { 20 } { 8 } - \frac { 1 } { 2 } = 1$$

Verify

Solution Steps

Reduce the fraction \frac{20}{8} to lowest terms by extracting and canceling out 4.

$$\frac{20}{3}+\frac{5}{2}-\frac{1}{2}=1$$

Least common multiple of 3 and 2 is 6. Convert \frac{20}{3} and \frac{5}{2} to fractions with denominator 6.

$$\frac{40}{6}+\frac{15}{6}-\frac{1}{2}=1$$

Since \frac{40}{6} and \frac{15}{6} have the same denominator, add them by adding their numerators.

$$\frac{40+15}{6}-\frac{1}{2}=1$$

Add 40 and 15 to get 55.

$$\frac{55}{6}-\frac{1}{2}=1$$

Least common multiple of 6 and 2 is 6. Convert \frac{55}{6} and \frac{1}{2} to fractions with denominator 6.

$$\frac{55}{6}-\frac{3}{6}=1$$

Since \frac{55}{6} and \frac{3}{6} have the same denominator, subtract them by subtracting their numerators.

$$\frac{55-3}{6}=1$$

Subtract 3 from 55 to get 52.

$$\frac{52}{6}=1$$

Reduce the fraction \frac{52}{6} to lowest terms by extracting and canceling out 2.

$$\frac{26}{3}=1$$

Convert 1 to fraction \frac{3}{3}.

$$\frac{26}{3}=\frac{3}{3}$$

Compare \frac{26}{3} and \frac{3}{3}.

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