Solve 20/28=20/42=28/5

$$\frac { 20 } { 28 } = \frac { 20 } { 42 } = \frac { 28 } { 5 }$$

Verify

Solution Steps

Reduce the fraction \frac{20}{28} to lowest terms by extracting and canceling out 4.

$$\frac{5}{7}=\frac{20}{42}\text{ and }\frac{20}{42}=\frac{28}{5}$$

Reduce the fraction \frac{20}{42} to lowest terms by extracting and canceling out 2.

$$\frac{5}{7}=\frac{10}{21}\text{ and }\frac{20}{42}=\frac{28}{5}$$

Least common multiple of 7 and 21 is 21. Convert \frac{5}{7} and \frac{10}{21} to fractions with denominator 21.

$$\frac{15}{21}=\frac{10}{21}\text{ and }\frac{20}{42}=\frac{28}{5}$$

Compare \frac{15}{21} and \frac{10}{21}.

$$\text{false}\text{ and }\frac{20}{42}=\frac{28}{5}$$

Reduce the fraction \frac{20}{42} to lowest terms by extracting and canceling out 2.

$$\text{false}\text{ and }\frac{10}{21}=\frac{28}{5}$$

Least common multiple of 21 and 5 is 105. Convert \frac{10}{21} and \frac{28}{5} to fractions with denominator 105.

$$\text{false}\text{ and }\frac{50}{105}=\frac{588}{105}$$

Compare \frac{50}{105} and \frac{588}{105}.

$$\text{false}\text{ and }\text{false}$$

The conjunction of \text{false} and \text{false} is \text{false}.

$$\text{false}$$