Solve 20^2+31^2-21^2/20*31

$$\frac { 20 ^ { 2 } + 31 ^ { 2 } - 21 ^ { 2 } } { 20 \times 31 }$$

Evaluate

$$\frac{46}{31}\approx 1.483870968$$

Solution Steps

Calculate 20 to the power of 2 and get 400.

$$\frac{400+31^{2}-21^{2}}{20\times 31}$$

Calculate 31 to the power of 2 and get 961.

$$\frac{400+961-21^{2}}{20\times 31}$$

Add 400 and 961 to get 1361.

$$\frac{1361-21^{2}}{20\times 31}$$

Calculate 21 to the power of 2 and get 441.

$$\frac{1361-441}{20\times 31}$$

Subtract 441 from 1361 to get 920.

$$\frac{920}{20\times 31}$$

Multiply 20 and 31 to get 620.

$$\frac{920}{620}$$

Reduce the fraction \frac{920}{620} to lowest terms by extracting and canceling out 20.

$$\frac{46}{31}$$

Factor

$$\frac{2 \cdot 23}{31} = 1\frac{15}{31} = 1.4838709677419355$$