Solve 20+29/frac{20{30}+29/40}=

$$\frac { 20 + 29 } { \frac { 20 } { 30 } + \frac { 29 } { 40 } } =$$

Evaluate

$$\frac{5880}{167}\approx 35.209580838$$

Solution Steps

Add 20 and 29 to get 49.

$$\frac{49}{\frac{20}{30}+\frac{29}{40}}$$

Reduce the fraction \frac{20}{30} to lowest terms by extracting and canceling out 10.

$$\frac{49}{\frac{2}{3}+\frac{29}{40}}$$

Least common multiple of 3 and 40 is 120. Convert \frac{2}{3} and \frac{29}{40} to fractions with denominator 120.

$$\frac{49}{\frac{80}{120}+\frac{87}{120}}$$

Since \frac{80}{120} and \frac{87}{120} have the same denominator, add them by adding their numerators.

$$\frac{49}{\frac{80+87}{120}}$$

Add 80 and 87 to get 167.

$$\frac{49}{\frac{167}{120}}$$

Divide 49 by \frac{167}{120} by multiplying 49 by the reciprocal of \frac{167}{120}.

$$49\times \frac{120}{167}$$

Express 49\times \frac{120}{167} as a single fraction.

$$\frac{49\times 120}{167}$$

Multiply 49 and 120 to get 5880.

$$\frac{5880}{167}$$

Factor

$$\frac{2 ^ {3} \cdot 3 \cdot 5 \cdot 7 ^ {2}}{167} = 35\frac{35}{167} = 35.209580838323355$$