Solve 2,6/sin65=c/sin90

$$\frac { 2,6 } { \sin 65 } = \frac { c } { \sin 90 }$$

Solve for c

$$c=\frac{13\sin(90)}{5\sin(65)}\approx 2.811212749$$

Steps for Solving Linear Equation

Swap sides so that all variable terms are on the left hand side.

$$\frac{c}{\sin(90)}=\frac{2,6}{\sin(65)}$$

The equation is in standard form.

$$\frac{1}{\sin(90)}c=\frac{13}{5\sin(65)}$$

Divide both sides by \left(\sin(90)\right)^{-1}.

$$\frac{\frac{1}{\sin(90)}c\sin(90)}{1}=\frac{13}{5\sin(65)\times \frac{1}{\sin(90)}}$$

Dividing by \left(\sin(90)\right)^{-1} undoes the multiplication by \left(\sin(90)\right)^{-1}.

$$c=\frac{13}{5\sin(65)\times \frac{1}{\sin(90)}}$$

Divide \frac{13}{5\sin(65)} by \left(\sin(90)\right)^{-1}.

$$c=\frac{13\sin(90)}{5\sin(65)}$$