Solve 2y^3*3xy^3/3x^2y^4

$$\frac { 2 y ^ { 3 } \times 3 x y ^ { 3 } } { 3 x ^ { 2 } y ^ { 4 } }$$

Evaluate

$$\frac{2y^{2}}{x}$$

Solution Steps

To multiply powers of the same base, add their exponents. Add 3 and 3 to get 6.

$$\frac{2y^{6}\times 3x}{3x^{2}y^{4}}$$

Cancel out 3xy^{4} in both numerator and denominator.

$$\frac{2y^{2}}{x}$$

Differentiate w.r.t. x

$$-2\times \left(\frac{y}{x}\right)^{2}$$