Solve for y
y=-4
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10\left(2y+3\right)=\left(3y+2\right)\times 5
Variable y cannot be equal to -\frac{2}{3} since division by zero is not defined. Multiply both sides of the equation by 10\left(3y+2\right), the least common multiple of 3y+2,10.
20y+30=\left(3y+2\right)\times 5
Use the distributive property to multiply 10 by 2y+3.
20y+30=15y+10
Use the distributive property to multiply 3y+2 by 5.
20y+30-15y=10
Subtract 15y from both sides.
5y+30=10
Combine 20y and -15y to get 5y.
5y=10-30
Subtract 30 from both sides.
5y=-20
Subtract 30 from 10 to get -20.
y=\frac{-20}{5}
Divide both sides by 5.
y=-4
Divide -20 by 5 to get -4.
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