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\frac{\left(2x-x^{2}\right)\left(x^{2}+2x+4\right)}{\left(x^{3}-8\right)x}
Divide \frac{2x-x^{2}}{x^{3}-8} by \frac{x}{x^{2}+2x+4} by multiplying \frac{2x-x^{2}}{x^{3}-8} by the reciprocal of \frac{x}{x^{2}+2x+4}.
\frac{x\left(-x+2\right)\left(x^{2}+2x+4\right)}{x\left(x-2\right)\left(x^{2}+2x+4\right)}
Factor the expressions that are not already factored.
\frac{-x\left(x-2\right)\left(x^{2}+2x+4\right)}{x\left(x-2\right)\left(x^{2}+2x+4\right)}
Extract the negative sign in 2-x.
-1
Cancel out x\left(x-2\right)\left(x^{2}+2x+4\right) in both numerator and denominator.