Solve 2x-7/3=4/15

$$\frac { 2 x - 7 } { 3 } = \frac { 4 } { 15 }$$

Solve for x

$$x = \frac{39}{10} = 3\frac{9}{10} = 3.9$$

Steps for Solving Linear Equation

Multiply both sides by 3.

$$2x-7=\frac{4}{15}\times 3$$

Express \frac{4}{15}\times 3 as a single fraction.

$$2x-7=\frac{4\times 3}{15}$$

Multiply 4 and 3 to get 12.

$$2x-7=\frac{12}{15}$$

Reduce the fraction \frac{12}{15} to lowest terms by extracting and canceling out 3.

$$2x-7=\frac{4}{5}$$

Add 7 to both sides.

$$2x=\frac{4}{5}+7$$

Convert 7 to fraction \frac{35}{5}.

$$2x=\frac{4}{5}+\frac{35}{5}$$

Since \frac{4}{5} and \frac{35}{5} have the same denominator, add them by adding their numerators.

$$2x=\frac{4+35}{5}$$

Add 4 and 35 to get 39.

$$2x=\frac{39}{5}$$

Divide both sides by 2.

$$x=\frac{\frac{39}{5}}{2}$$

Express \frac{\frac{39}{5}}{2} as a single fraction.

$$x=\frac{39}{5\times 2}$$

Multiply 5 and 2 to get 10.

$$x=\frac{39}{10}$$