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\left(2x+2\right)\left(2x-2\right)=\left(4x-1\right)\left(x-1\right)
Variable x cannot be equal to any of the values -1,\frac{1}{4} since division by zero is not defined. Multiply both sides of the equation by 2\left(4x-1\right)\left(x+1\right), the least common multiple of 4x-1,2x+2.
\left(2x\right)^{2}-4=\left(4x-1\right)\left(x-1\right)
Consider \left(2x+2\right)\left(2x-2\right). Multiplication can be transformed into difference of squares using the rule: \left(a-b\right)\left(a+b\right)=a^{2}-b^{2}. Square 2.
2^{2}x^{2}-4=\left(4x-1\right)\left(x-1\right)
Expand \left(2x\right)^{2}.
4x^{2}-4=\left(4x-1\right)\left(x-1\right)
Calculate 2 to the power of 2 and get 4.
4x^{2}-4=4x^{2}-5x+1
Use the distributive property to multiply 4x-1 by x-1 and combine like terms.
4x^{2}-4-4x^{2}=-5x+1
Subtract 4x^{2} from both sides.
-4=-5x+1
Combine 4x^{2} and -4x^{2} to get 0.
-5x+1=-4
Swap sides so that all variable terms are on the left hand side.
-5x=-4-1
Subtract 1 from both sides.
-5x=-5
Subtract 1 from -4 to get -5.
x=\frac{-5}{-5}
Divide both sides by -5.
x=1
Divide -5 by -5 to get 1.