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3\left(2x-1\right)-5x\geq x-5
Multiply both sides of the equation by 15, the least common multiple of 5,3,15. Since 15 is positive, the inequality direction remains the same.
6x-3-5x\geq x-5
Use the distributive property to multiply 3 by 2x-1.
x-3\geq x-5
Combine 6x and -5x to get x.
x-3-x\geq -5
Subtract x from both sides.
-3\geq -5
Combine x and -x to get 0.
x\in \mathrm{R}
This is true for any x.