Solve 2x/I^2=a

$$\frac { 2 x } { I ^ { 2 } } = a$$

Solve for a

$$a=\frac{2x}{I^{2}}$$

$$I\neq 0$$

Steps for Solving Linear Equation

Multiply both sides of the equation by I^{2}.

$$2x=aI^{2}$$

Swap sides so that all variable terms are on the left hand side.

$$aI^{2}=2x$$

The equation is in standard form.

$$I^{2}a=2x$$

Divide both sides by I^{2}.

$$\frac{I^{2}a}{I^{2}}=\frac{2x}{I^{2}}$$

Dividing by I^{2} undoes the multiplication by I^{2}.

$$a=\frac{2x}{I^{2}}$$

Solve for I (complex solution)

$$\left\{\begin{matrix}I=-a^{-\frac{1}{2}}\sqrt{2x}\text{; }I=a^{-\frac{1}{2}}\sqrt{2x}\text{, }&x\neq 0\text{ and }a\neq 0\\I\neq 0\text{, }&a=0\text{ and }x=0\end{matrix}\right.$$

Solve for I

$$\left\{\begin{matrix}I=\sqrt{\frac{2x}{a}}\text{; }I=-\sqrt{\frac{2x}{a}}\text{, }&\left(a<0\text{ and }x<0\right)\text{ or }\left(a>0\text{ and }x>0\right)\\I\neq 0\text{, }&a=0\text{ and }x=0\end{matrix}\right.$$