Evaluate
\frac{2\sqrt{3}x}{9y}
Differentiate w.r.t. x
\frac{2\sqrt{3}}{9y}
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\frac{2x\sqrt{3}}{3y\left(\sqrt{3}\right)^{2}}
Rationalize the denominator of \frac{2x}{3y\sqrt{3}} by multiplying numerator and denominator by \sqrt{3}.
\frac{2x\sqrt{3}}{3y\times 3}
The square of \sqrt{3} is 3.
\frac{2x\sqrt{3}}{9y}
Multiply 3 and 3 to get 9.
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Limits
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