Solve 2x^2/9xy*-6xy^2z/4x^2=

$$\frac { 2 x ^ { 2 } } { 9 x y } \cdot \frac { - 6 x y ^ { 2 } z } { 4 x ^ { 2 } } =$$

Evaluate

$$-\frac{yz}{3}$$

Solution Steps

Cancel out x in both numerator and denominator.

$$\frac{2x}{9y}\times \frac{-6xy^{2}z}{4x^{2}}$$

Cancel out 2x in both numerator and denominator.

$$\frac{2x}{9y}\times \frac{-3zy^{2}}{2x}$$

Multiply \frac{2x}{9y} times \frac{-3zy^{2}}{2x} by multiplying numerator times numerator and denominator times denominator.

$$\frac{2x\left(-3\right)zy^{2}}{9y\times 2x}$$

Cancel out 2\times 3xy in both numerator and denominator.

$$\frac{-yz}{3}$$

Differentiate w.r.t. z

$$-\frac{y}{3}$$