Solve for x
x=\frac{3y+8}{7}
Solve for y
y=\frac{7x-8}{3}
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2\left(2x+y\right)+3x-5y=8
Multiply both sides of the equation by 4, the least common multiple of 2,4.
4x+2y+3x-5y=8
Use the distributive property to multiply 2 by 2x+y.
7x+2y-5y=8
Combine 4x and 3x to get 7x.
7x-3y=8
Combine 2y and -5y to get -3y.
7x=8+3y
Add 3y to both sides.
7x=3y+8
The equation is in standard form.
\frac{7x}{7}=\frac{3y+8}{7}
Divide both sides by 7.
x=\frac{3y+8}{7}
Dividing by 7 undoes the multiplication by 7.
2\left(2x+y\right)+3x-5y=8
Multiply both sides of the equation by 4, the least common multiple of 2,4.
4x+2y+3x-5y=8
Use the distributive property to multiply 2 by 2x+y.
7x+2y-5y=8
Combine 4x and 3x to get 7x.
7x-3y=8
Combine 2y and -5y to get -3y.
-3y=8-7x
Subtract 7x from both sides.
\frac{-3y}{-3}=\frac{8-7x}{-3}
Divide both sides by -3.
y=\frac{8-7x}{-3}
Dividing by -3 undoes the multiplication by -3.
y=\frac{7x-8}{3}
Divide 8-7x by -3.
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