Solve 2x+3/5=2-x/3+x

$$\frac { 2 x + 3 } { 5 } = 2 \frac { - x } { 3 } + x$$

Solve for x

$$x=-9$$

Steps for Solving Linear Equation

Multiply both sides of the equation by 15, the least common multiple of 5,3.

$$3\left(2x+3\right)=10\left(-x\right)+15x$$

Use the distributive property to multiply 3 by 2x+3.

$$6x+9=10\left(-x\right)+15x$$

Subtract 10\left(-x\right) from both sides.

$$6x+9-10\left(-x\right)=15x$$

Subtract 15x from both sides.

$$6x+9-10\left(-x\right)-15x=0$$

Multiply -1 and 10 to get -10.

$$6x+9-10\left(-1\right)x-15x=0$$

Multiply -10 and -1 to get 10.

$$6x+9+10x-15x=0$$

Combine 6x and 10x to get 16x.

$$16x+9-15x=0$$

Combine 16x and -15x to get x.

$$x+9=0$$

Subtract 9 from both sides. Anything subtracted from zero gives its negation.

$$x=-9$$