Solve for x
x=0
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2\left(2x+1\right)-5\left(x+1\right)=2x-3
Multiply both sides of the equation by 10, the least common multiple of 5,2,10.
4x+2-5\left(x+1\right)=2x-3
Use the distributive property to multiply 2 by 2x+1.
4x+2-5x-5=2x-3
Use the distributive property to multiply -5 by x+1.
-x+2-5=2x-3
Combine 4x and -5x to get -x.
-x-3=2x-3
Subtract 5 from 2 to get -3.
-x-3-2x=-3
Subtract 2x from both sides.
-3x-3=-3
Combine -x and -2x to get -3x.
-3x=-3+3
Add 3 to both sides.
-3x=0
Add -3 and 3 to get 0.
x=0
Product of two numbers is equal to 0 if at least one of them is 0. Since -3 is not equal to 0, x must be equal to 0.
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{ x } ^ { 2 } - 4 x - 5 = 0
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4 \sin \theta \cos \theta = 2 \sin \theta
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y = 3x + 4
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Matrix
\left[ \begin{array} { l l } { 2 } & { 3 } \\ { 5 } & { 4 } \end{array} \right] \left[ \begin{array} { l l l } { 2 } & { 0 } & { 3 } \\ { -1 } & { 1 } & { 5 } \end{array} \right]
Simultaneous equation
\left. \begin{cases} { 8x+2y = 46 } \\ { 7x+3y = 47 } \end{cases} \right.
Differentiation
\frac { d } { d x } \frac { ( 3 x ^ { 2 } - 2 ) } { ( x - 5 ) }
Integration
\int _ { 0 } ^ { 1 } x e ^ { - x ^ { 2 } } d x
Limits
\lim _{x \rightarrow-3} \frac{x^{2}-9}{x^{2}+2 x-3}