Solve 2x+1/3-1=x

$$\frac { 2 x + 1 } { 3 } - 1 = x$$

Solve for x

$$x=-2$$

Steps for Solving Linear Equation

Divide each term of 2x+1 by 3 to get \frac{2}{3}x+\frac{1}{3}.

$$\frac{2}{3}x+\frac{1}{3}-1=x$$

Convert 1 to fraction \frac{3}{3}.

$$\frac{2}{3}x+\frac{1}{3}-\frac{3}{3}=x$$

Since \frac{1}{3} and \frac{3}{3} have the same denominator, subtract them by subtracting their numerators.

$$\frac{2}{3}x+\frac{1-3}{3}=x$$

Subtract 3 from 1 to get -2.

$$\frac{2}{3}x-\frac{2}{3}=x$$

Subtract x from both sides.

$$\frac{2}{3}x-\frac{2}{3}-x=0$$

Combine \frac{2}{3}x and -x to get -\frac{1}{3}x.

$$-\frac{1}{3}x-\frac{2}{3}=0$$

Add \frac{2}{3} to both sides. Anything plus zero gives itself.

$$-\frac{1}{3}x=\frac{2}{3}$$

Multiply both sides by -3, the reciprocal of -\frac{1}{3}.

$$x=\frac{2}{3}\left(-3\right)$$

Express \frac{2}{3}\left(-3\right) as a single fraction.

$$x=\frac{2\left(-3\right)}{3}$$

Multiply 2 and -3 to get -6.

$$x=\frac{-6}{3}$$

Divide -6 by 3 to get -2.

$$x=-2$$