Solve for b
b\in \mathrm{R}
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2\left(2b-1\right)-1=4b-3
Multiply both sides of the equation by 4, the least common multiple of 2,4.
4b-2-1=4b-3
Use the distributive property to multiply 2 by 2b-1.
4b-3=4b-3
Subtract 1 from -2 to get -3.
4b-3-4b=-3
Subtract 4b from both sides.
-3=-3
Combine 4b and -4b to get 0.
\text{true}
Compare -3 and -3.
b\in \mathrm{R}
This is true for any b.
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