Solve 2b^5/9-5/6b^6+17b^6/8

$$\frac { 2 b ^ { 5 } } { 9 } - \frac { 5 } { 6 } b ^ { 6 } + \frac { 17 b ^ { 6 } } { 8 }$$

Factor

$$\frac{\left(93b+16\right)b^{5}}{72}$$

Solution Steps

Factor out \frac{1}{72}.

$$\frac{16b^{5}-60b^{6}+153b^{6}}{72}$$

Consider 16b^{5}-60b^{6}+153b^{6}. Factor out b^{5}.

$$b^{5}\left(16-60b+153b\right)$$

Consider 16-60b+153b. Multiply and combine like terms.

$$93b+16$$

Rewrite the complete factored expression.

$$\frac{b^{5}\left(93b+16\right)}{72}$$

Evaluate

$$\frac{31b^{6}}{24}+\frac{2b^{5}}{9}$$