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\frac{\left(2x+3\right)\left(a+b\right)}{a+b}-2
Factor the expressions that are not already factored in \frac{2ax+3b+2xb+3a}{a+b}.
2x+3-2
Cancel out a+b in both numerator and denominator.
2x+1
Subtract 2 from 3 to get 1.
\frac{\left(2x+3\right)\left(a+b\right)}{a+b}-2
Factor the expressions that are not already factored in \frac{2ax+3b+2xb+3a}{a+b}.
2x+3-2
Cancel out a+b in both numerator and denominator.
2x+1
Subtract 2 from 3 to get 1.