Solve 2a3b/4=20

$$\frac { 2 a 3 b } { 4 } = 20$$

Solve for a_3

$$a_{3}=\frac{40}{b}$$

$$b\neq 0$$

Steps for Solving Linear Equation

Multiply both sides by 4.

$$2a_{3}b=20\times 4$$

Multiply 20 and 4 to get 80.

$$2a_{3}b=80$$

The equation is in standard form.

$$2ba_{3}=80$$

Divide both sides by 2b.

$$\frac{2ba_{3}}{2b}=\frac{80}{2b}$$

Dividing by 2b undoes the multiplication by 2b.

$$a_{3}=\frac{80}{2b}$$

Divide 80 by 2b.

$$a_{3}=\frac{40}{b}$$

Solve for b

$$b=\frac{40}{a_{3}}$$

$$a_{3}\neq 0$$

Steps for Solving Linear Equation

Multiply both sides by 4.

$$2a_{3}b=20\times 4$$

Multiply 20 and 4 to get 80.

$$2a_{3}b=80$$

Divide both sides by 2a_{3}.

$$\frac{2a_{3}b}{2a_{3}}=\frac{80}{2a_{3}}$$

Dividing by 2a_{3} undoes the multiplication by 2a_{3}.

$$b=\frac{80}{2a_{3}}$$

Divide 80 by 2a_{3}.

$$b=\frac{40}{a_{3}}$$